Answer:
Step-by-step explanation:
Given that four people are on the team. Members will be chosen randomly to serve as chairperson, treasurer, secretary, or timekeeper
Since one person cannot serve two posts we have total number of ways
= 4(3)(2)(1) = 24
If Noor is chair person and Qu treasurer then remaining 2 can take two posts in 2 different ways
So probability that Noor is selected to be chairperson and Qu is selected to be treasurer
=favourable outcomes/total outcomes
= [tex]\frac{2}{24} \\=0.083[/tex]