Question

Two circular loops of wire, each containing a single turn, have the same radius of 3.40 cm and a common center. The planes of the loops are perpendicular. Each carries a current of 1.80 A. What is the magnitude of the net magnetic field at the common center?

Answer 1

Answer: To solve for the net magnetic field of two circular loops of wire, each containing a single turn

B net= √[( NUI / 2R)^2 × ( NUI / 2R)^2]

Where B net = Net magnetic field

B net = √2 × (NUI/ 2R)

B net =[ √2 × 1 × ( 4 × 3.142 × 10^-7) × (1.8)] ÷ 2 × 0.034

B net = { 1.414 × (0.00000126) × (1.8)}÷ 0.068

B net = 4.72 × 10^-5 T