Respuesta :
Answer:a) ∆E=-0.077KJ (exothermic)
b) ∆E = 110KJ (endothermic)
Explanation:
a) ∆E = q + w
q= 0.763 KJ
w= -840J = -0.840 KJ
∆E = 0.763-0.840 = - 0.077KJ
Exothermic reaction are those reactions that proceeds with the release of heat to the surroundings and Energy is negative in exothermic processes.
b)/∆E = q+w
q= 66.1KJ, w=44KJ
∆E = 101KJ
And it is endothermic
When work is done on a system, the international energy increases.
Answer: a) E= -0.077KJ Exothermic
b) E= -22.1KJ Exothermic
Explanation:
a) change internal energy E = q+ w
Since q= 0.763KJ and w=-840j= -0.84KJ
E= 0.763kj - 0.84kj
E= -0.077KJ
The process is exothermic since it releases heat to the surrounding i.e E is negative.
b) q= - 66.1KJ negative because it's heat released to the surrounding
w= 44.0KJ work done on the system by the surrounding.
E= q+w
E= -66.1KJ + 44.0KJ
E= -22.1KJ
The process is exothermic because the value of E is negative.
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