Using the distributive property to find the product (y – 4)(y2 + 4y + 16) results in a polynomial of the form y3 + 4y2 + ay – 4y2 – ay – 64. What is the value of a in the polynomial?

Respuesta :

(y - 4)(y^2 + 4y + 16) = y^3 + 4y^2 + 16y - 4y^2 - 16y - 64

Therefore, a = 16.

For this case we have the following expression:

[tex](y - 4) (y ^ 2 + 4y + 16)[/tex]

Using the distributive property, we have:

[tex]y (y ^ 2 + 4y + 16) -4 (y ^ 2 + 4y + 16)[/tex]

Rewriting the expression we have:

[tex]y^ 3 + 4y ^ 2 + 16y - 4y ^ 2 - 16y - 64[/tex]

Comparing with the given expression we have:

[tex]y ^ 3 + 4y ^ 2 + ay - 4y ^ 2 - ay - 64 = y ^ 3 + 4y ^ 2 + 16y - 4y ^ 2 - 16y - 64[/tex]

From where we conclude that:

[tex]a = 16[/tex]

Answer:

The value of a in the polynomial is:

[tex]a = 16[/tex]


Otras preguntas

ACCESS MORE