Question

A student standing on the roof of a 50 meter high building kicks a stone at a horizontal speed of 4 meters per second. How much time is required for the stone to reach the ground

Answer 1

Answer:

3.19 seconds

Explanation:

Using equation of projectile motion

$s=ut+0.5gt^{2}$ where s is distance, u is initial velocity, g is acceleration due to gravity and t is time, but here s and g are negative since the ball is moving downwards

Substituting initial velocity u as 0, s as 50m we obtain and g as $9.81 m/s^{2}$

$50=0+0.5*9.81t^{2}$

$t=\sqrt {(\frac {50}{0.5*9.81})}$

t=3.1927542840 seconds

t=3.19 seconds

Answer 2

3.19 sec time is required for the stone to reach the ground.

Given :

Height = 50 m

Horizontal Speed = 4 m/sec

Acceleration due to Gravity = 9.81 $\rm m /sec^2$

Solution :

We know that displacement is given by

$\rm s = ut+\dfrac{1}{2} at^2$

$\rm 50 = 0 +(0.5\times 9.81 \times t^2)$

$\rm t = \sqrt{\dfrac{50}{0.5\times 9.81}}$

t = 3.19 sec

3.19 sec time is required for the stone to reach the ground.

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