Question

A 2.0 kg book is lying on a 0.75-m-high table. You pick it up and place it on a bookshelf 2.3 m above the floor. During this process,

Answer 1

Answer:

The gravitational potential energy gained by the book is 30.4 J

Explanation:

The change in gravitational potential energy of an object is given by

$\Delta U = mg \Delta h$

where

m is the mass of the object

g is the acceleration of gravity

$\Delta h$ is the change in height of the object

For the book in this problem,

m = 2.0 kg

g = 9.8 m/s^2

$\Delta h = 2.3 m - 0.75 m =1.55 m$

Substituting into the equation, we find

$\Delta U = (2.0)(9.8)(1.55)=30.4 J$

Answer 2

The amount of work done by gravity on the 2.0 Kg book is 30.38 J

What is potential energy?

This is the energy possessed by an object by virtue of its position. It can be expressed mathematically as:

Potential energy (PE) = mass (m) × Acceleration due to gravity (g) × height (h)

PE = mgh

How to determine the workdone

• Mass (m) = 2 Kg
• Acceleration due to gravity (g) = 9.8 m/s²
• Initial height = 0.75 m
• Final height = 2.3 m
• Change in height (Δh) = 2.3 – 0.75 = 1.55 m

• Workdone (Wd) =?

Wd = mgΔh

Wd = 2 × 9.8 × 1.55

Wd = 30.38 J

Complete question:

A 2.0 kg book is lying on a 0.75-m-high table. You pick it up and place it on a bookshelf 2.3 m above the floor. During this process, how much work does gravity do on the book?

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