Respuesta :
[tex]a^2 + b^2 = c^2\\\\30^2 +b^2= 50^2\\\\b^2 = 50^2 - 30^2\\\\c = \sqrt{1600}\\\\c =40[/tex]
The length of the other leg is 40 millimeters.
The length of the other leg is 40 millimeters.
Hey there,Lets solve this problem together.
We know that the hypotenuse of a right triangle is 50 millimeters long. One leg of the right triangle is 30 millimeters long.
Hypotenuse = c²
= 50
α² = 30
-------------- Calculations
[tex] \alpha^2 + \beta^2 = c^2[/tex]
[tex]30^2 + \beta ^2 = c^2 [/tex]
[tex] \beta ^2 = c^2(50) - a^2(30)[/tex]
[tex]cb = \sqrt{1600} [/tex]
[tex]C = 40[/tex]
We know that the hypotenuse of a right triangle is 50 millimeters long. One leg of the right triangle is 30 millimeters long.
Hypotenuse = c²
= 50
α² = 30
-------------- Calculations
[tex] \alpha^2 + \beta^2 = c^2[/tex]
[tex]30^2 + \beta ^2 = c^2 [/tex]
[tex] \beta ^2 = c^2(50) - a^2(30)[/tex]
[tex]cb = \sqrt{1600} [/tex]
[tex]C = 40[/tex]