Question

6x2 + 41x + 63
Factoring

Answer 1

The factors of given polynomial are:$(2x+9)(3x+7)$

Further explanation:

Factorization is either done by using quardatic formula or directly making factor.

For making factors, the constant term is multiplied with the coefficient of x^2 and pairs of factors are made such that their sum or difference is equal to the co-efficient of x.

Given

$6x^2+41x+63$

63x6 gives us: 378

Factor pairs of 378 are:

182,2

126,3

54,7

42,9

14,27 => 41

So the pair we are going to use is 14,27

$6x^2+41x+63\\=6x^2+14x+27x+63\\=2x(3x+7)+9(3x+7)\\=(2x+9)(3x+7)$

So the factors of given polynomial are:$(2x+9)(3x+7)$

Keywords: Factorization, polynomials

Learn more about factorization at:

• brainly.com/question/4550858
• brainly.com/question/1414350

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