Question

7. Divide using long division.(3x - 3x2 - 4x+3)+(x+3)3xBx-403x? - 12x+32, R-933x + 6x-40, R 993x - 12x+32

Answer 1

The dividend given is,

$3x^3-3x^2-4x+3$

The divisor given is,

$x+3$

Apply the long division method to find the quotient and remainder,

$\sqrt[x+3]{3x^3}-3x^2-4x+3$