Respuesta :
Answer:
Simple interest [tex][P+P\times \frac{r}{100} \times n][/tex]
Compound interest [tex]P[1+\frac{r}{100} ]^{n}[/tex]
Step-by-step explanation:
If a certain sum of money P is increasing at a rate of r% simple interest annually, then after n years the increases sum will become [tex]P[1+\frac{r}{100}\times n]\textrm {i.e.}[P+P\times \frac{r}{100} \times n][/tex]
Therefore, in simple interest the interest is calculated on the fixed principal amount P.
So, after 1 year the sum will become [tex][P + P \times \frac{r}{100} ][/tex]
After 2 years the sum will become [tex][P + (P \times \frac{r}{100})+(P \times \frac{r}{100}) ][/tex]
Therefore, in each year the sum is increasing by a fixed amount and it is the simple interest which is calculated on the principal P always.
But, if we consider P is increasing at a rate of r% interest annually and is compounded every year then after n consecutive years the sum will become [tex]P[1+\frac{r}{100} ]^{n}[/tex].
So, after first year the sum will become [tex][P + P \times \frac{r}{100} ][/tex].
After 2 years the sum will become [tex][P + P \times \frac{r}{100} ] +[P + P \times \frac{r}{100} ] \times \frac{r}{100}[/tex]
Therefore, in the 2nd year the interest is calculated on [tex][P + P \times \frac{r}{100} ][/tex] i.e. the principal after one year but not on P only.
Similarly the interest after 3rd year will be calculated on the principal that becomes after 2 years. (Answer)
Answer:
Simple interest is based on the principal amount of a loan or deposit. In contrast, compound interest is based on the principal amount and the interest that accumulates on it in every period.
Step-by-step explanation: