Answer:
a. A = -1 and B = 1
b. A = 7 and B = -5
Step-by-step explanation:
a.
[tex]\frac{A}{x+1} +\frac{B}{x-1} = \frac{2}{x^2-1}[/tex]
[tex]\frac{A*(x-1)+B*(x+1)}{(x+1)*(x-1)} = \frac{2}{x^2-1}[/tex]
[tex]\frac{Ax - A + Bx + B}{x^2 -1} = \frac{2}{x^2-1}[/tex]
To the equation be true, the "x-parts" and "nonx-parts" mist be the same, so:
Ax + Bx = 0
(A + B)x = 0
A + B = 0
A = -B
B - A = 2
B - (-B) = 2
2B = 2
B = 1 and A = -1
b.
[tex]\frac{A}{x+3} + \frac{B}{x +2} = \frac{2x -1}{x^2+5x+6}[/tex]
[tex]\frac{A*(x+2) + B*(x+3)}{(x+3)*(x+2)} = \frac{2x-1}{x^2+5x+6}[/tex]
[tex]\frac{Ax + 2A + Bx + 3B}{x^2 + 5x + 6} = \frac{2x-1}{x^2+5x+6}[/tex]
To the equation be true, the "x-parts" and "nonx-parts" mist be the same, so:
Ax + Bx = 2x
(A + B)x = 2x
A + B = 2
A = 2 - B
2A + 3B = -1
2*(2-B) + 3B = -1
4 - 2B + 3B = -1
B = -5 and A = 2 - (-5) = 7