Respuesta :
amount left=amount now-deducted
deducted=amount deducted each time times number of times
amount deducted each time =1.25
x=number of times
so
32=amount now
1.25x is deducted
so the amount left has to be greater than or equal to 10
32-1.25x≥10
minus 1.25x both sides
32≥10+1.25x
minus 10 both sides
22≥1.25x
divide both sides by 1.25
17.6≥x
you can't pass through 0.6 times so 17 times is max
the inequality is
32-1.25x≥10 whre x is the number of times that he passes
deducted=amount deducted each time times number of times
amount deducted each time =1.25
x=number of times
so
32=amount now
1.25x is deducted
so the amount left has to be greater than or equal to 10
32-1.25x≥10
minus 1.25x both sides
32≥10+1.25x
minus 10 both sides
22≥1.25x
divide both sides by 1.25
17.6≥x
you can't pass through 0.6 times so 17 times is max
the inequality is
32-1.25x≥10 whre x is the number of times that he passes