Answer:
x ≥ 2
Step-by-step explanation:
d) 6 - 5x ≤ 2 - 3x
6 - 2 ≤ 5x - 3x
4 ≤ 2x
2 ≤ x
Or...
[tex]2 \leqslant x[/tex]
The process is shown in the photo