Question

The function p(x)=x(x-5)(x-2)(x+3) has four zeros. What is the smallest

Answer 1

you can get the zeros by equating each factor by zero
so we have 0 , 5 , 2 , -3
so the smallest one is (-3)

Answer 2

Answer: The smallest zero is -3.

Step-by-step explanation:

Zeros of a function are the values of input for which the function gives 0 output.

Here, the given function is,

p(x) = x(x-5)(x-2)(x+3)

For finding the zeroes of p(x),

p(x) = 0

⇒ x(x-5)(x-2)(x+3) = 0,

⇒ x = 0 or x - 5 = 0 or x-2=0 or x+3=0

⇒ x = 0 or x = 5 or x = 2 or x = -3

Thus, the zeros of the given function are 0, 5, 2, -3

In which -3 is smallest.