Answer:
[tex]\large\boxed{B\subset A}[/tex]
Step-by-step explanation:
[tex]\O\subset A-\bold{TRUE}\ \text{because the empty set is a subset of any set}\\\\B\subseteq B-\bold{TRUE}\ \text{because}\ B=B\\\\B\subset A-\bold{FALSE}\ \text{because}:\\\\A=\{4,\ 7,\ 10,\ 13,\ 17\},\ B=\{3,\ 5,\ 7,\ 9\}\\\\3\notin A,\ 5\notin A\ \text{and}\ 9\notin A\\\\\text{For}\ B\subset A\ \text{, each element of set B must be in set A.}[/tex]
