Answer:
The equation of the line with slope -3 and passes through (2,-1) is y = -3x + 5
Solution:
In the question it is given that the line passes through the point (2,-1) with slope (m) = -3. We have to find out the point slope form and slope intercept form of the equation.
We know the point - slope form of an equation is given by
[tex]\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)[/tex]
[tex]\text { Here } y_{1}=-1 \text { and } x_{1}=2 \text { and the slope } m=-3[/tex]
Substituting the values in the point slope form of the equation we get
(y-(-1)) = -3(x-2)
(y+1) = -3 (x-2) is the point slope form of given line
We know the slope intercept form of a line is given by
y = mx +c
Here y = -1 , x = 2 and m = -3
Substituting the values in slope intercept form equation we get
-1 = (-3)2 + c
⇒-1 = -6 + c
⇒-1+6 = c
c = 5
Thus the slope intercept form of equation is y = -3x+5