Question

Calculate the initial velocity of a baseball ball so you can make a home run. Assume the angle that the initial speed makes with the horizontal θ=29degrees.
Length of the baseball field is x=100m, height of fence is 3.5m.

Answer 1

Answer:35.13 m/s

Explanation:

Given

launching angle$=29^{\circ}$

Length of baseball field=100 m

height of fence=3.5 m

we know trajectory of projectile is given by

$y=xtan\theta -\frac{gx^2}{2u^2cos^\theta }$

where y=vertical distance

x=horizontal distance

u=initial velocity

$\theta$=launch angle

here y=3.5 m

x=100

$\theta =29^{\circ}$

$3.5=100\times tan(29)-\frac{9.8\times 100^2}{2u^2(cos29)^2}$

$\frac{64121.0306}{u^2}=100tan29-3.5$

$u^2=1234.7374$

u=35.13 m/s