Respuesta :
Answer:
The final pressure is 173 kPa.
Explanation:
A mixture of gases at an initial pressure of P₁ = 101 kPa is compressed from an initial volume V₁ = 7.20 dm³ to a final volume V₂ = 4.21 dm³. If we suppose an ideal gas behavior and that temperature remains constant, we can apply Boyle's law to find out the final pressure P₂:
P₁ . V₁ = P₂ . V₂
[tex]P_{2}=\frac{P_{1}.V_{1}}{V_{2}}=\frac{101kPa.7.20dm^{3} }{4.21dm^{3} } =173kPa[/tex]
Explanation:
According to Boyle's law, volume of a gas is inversely proportional to its pressure at a constant temperature.
Mathematically, [tex]P \propto \frac{1}{V}[/tex]; at constant T
It is given that,
[tex]P_{1}[/tex] = 101 kPa, [tex]P_{2}[/tex] = ?
[tex]V_{1} = 7.20 dm^{3}[/tex], [tex]V_{2} = 4.21 dm^{3}[/tex]
We will calculate the final pressure as follows.
[tex]P_{1}V_{1} = P_{2}V_{2}[/tex]
[tex]101 kPa \times 7.20 dm^{3} = P_{2} \times 4.21 dm^{3}[/tex]
[tex]P_{2} = \frac{101 kPA \times 7.20 dm^{3}}{4.21 dm^{3}}[/tex]
= 172.73 kPa
Thus, we can conclude that the final pressure of the gas is 172.73 kPa.