Answer:
PE=0.29J
Explanation:
According to the description, there is a angle and in point swung upward of 70°
So,
[tex]Y=13*10^{-2}*cos(70) \\Y=0.0444m[/tex]
Appling the equation of Potential Energy we have,
[tex]PE=mgh\\PE=(0.35)(9.8)(0.13-0.0444)\\PE=0.29J[/tex]