Question

A student with mass 54 kg jumps off a high diving board. Part A Using 6.0×1024 kg for the mass of the earth, what is the acceleration of the earth toward her as she accelerates toward the earth with an acceleration of 9.8 m/s2 ? Assume that the net force on the earth is the force of gravity she exerts on it.

Answer 1

Answer:

a = 8.82 × 10⁻²³ m/s²

Explanation:

given,

mass of the student = 54 kg

mass of the earth = 6 × 10²⁴ kg

acceleration due to gravity = 9.8 m/s²

force exerted by the student

F = m g

F = 54 × 9.8

  = 529.2 N

acceleration of the earth

F = m a

a = $\dfrac{F}{m}$

a = $\dfrac{529.2}{6\times 10^{24}}$

a = 88.2 × 10⁻²⁴ m/s²

a = 8.82 × 10⁻²³ m/s²

hence, the acceleration of the earth is equal to a = 8.82 × 10⁻²³ m/s²