Respuesta :
Answer:
Product of the roots of the equation [tex]\bold{\frac{1}{2} x^{2}-\frac{5}{4} x-3=0}[/tex] is -6
Solution:
If [tex]\alpha[/tex] and [tex]\beta[/tex] are the roots of any quadratic equation [tex]x^{2}+b x+c=0[/tex] then,
Sum of roots [tex]\alpha+\beta=-\frac{b}{a}[/tex]
Product of roots [tex]\alpha \times \beta[/tex] = [tex]\frac{c}{a}[/tex]
Given that
[tex]\frac{1}{2} x^{2}-\frac{5}{4} x-3=0[/tex]
On simplifying the above equation,
[tex]\frac{2 x^{2}-5 x-12}{4}=0[/tex]
[tex]2 x^{2}-5 x-12=0[/tex]
Here a = 2, b = -5 and c = -12
So product of roots is [tex]\frac{c}{a}[/tex] that is [tex]\frac{-12}{2} = -6[/tex]
Hence product of the roots of the equation [tex]\frac{1}{2} x^{2}-\frac{5}{4} x-3=0[/tex] is -6