Respuesta :

Step-by-step explanation:

(X-4)(2x+3)=0

X-4=0 2x+3=0

X=4 X=-3/2

Answer:

Product of the roots of the equation [tex]\bold{\frac{1}{2} x^{2}-\frac{5}{4} x-3=0}[/tex] is -6

Solution:

If [tex]\alpha[/tex] and [tex]\beta[/tex] are the roots of any quadratic equation [tex]x^{2}+b x+c=0[/tex] then,

Sum of roots [tex]\alpha+\beta=-\frac{b}{a}[/tex]

Product of roots [tex]\alpha \times \beta[/tex] = [tex]\frac{c}{a}[/tex]

Given that

[tex]\frac{1}{2} x^{2}-\frac{5}{4} x-3=0[/tex]

On simplifying the above equation,

[tex]\frac{2 x^{2}-5 x-12}{4}=0[/tex]

[tex]2 x^{2}-5 x-12=0[/tex]

Here a = 2, b = -5  and  c = -12

So product of roots is  [tex]\frac{c}{a}[/tex] that is [tex]\frac{-12}{2} = -6[/tex]

Hence product of the roots of the equation [tex]\frac{1}{2} x^{2}-\frac{5}{4} x-3=0[/tex] is -6

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