On average, an eye blink lasts about 100 ms. How far does a fighter jet travel during a pilot's blink if the plane's average velocity is 3650 km/h?

Respuesta :

Answer:

Distance, d = 101.388 meters

Explanation:

It is given that,

The average velocity of plane, v = 3650 km/h = 1013.88 m/s

The time for which eye blinks, [tex]t=100\ ms=0.1\ s[/tex]

Let d is the distance covered by the jet. It can be calculated as :

[tex]d=v\times t[/tex]

[tex]d=1013.88\ m/s\times 0.1\ s[/tex]        

d = 101.388 meters

So, the distance covered by a fighter jet during a pilot's blink is 101.388 meters. Hence, this is the required solution.                                                                              

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