Question

A balloon filled with helium has a volume of 4.6 x 103 L at 31°C. What volume will the balloon occupy at 56°C if the pressure surrounding the balloon remains constant? Be sure to answer all parts. Enter your answer in scientific notation. x 10 (select) ^L

Answer 1

Answer:

5x10^3 L

Explanation:

Charle's Law states that the volume of a fixed amount of gas maintained at constant pressure is directly proportional to the absolute temperature of the gas, for a constant amount of gas we can write:

$\frac{V1}{T1}=\frac{V2}{T2}$

As the pressure of the balloon doesn't change, we can use Charle's Law to solve the problem. Firs we change the given temperatures to absolute temperature units ( °K), using the following relations:

°K=273,15+°C

Therefore:

V1=4.6 x 10^3 L, T1=273,15+31=304,15°K

V2=?,                   T2=273,15+56=329,15°K

$V2=\frac{V1T2}{T1}=\frac{4.6*10^3*329,15}{304,15}=4978,1L=5*10^3L$

The new volume of the balloon is 5x10^3 L.