Answer: 0.2415
Step-by-step explanation:
Given : There are 5 Snickers, 10 Baby Ruths, 13 Milky Ways, 12 Twixs and17 Almond Joys in a bowl of candy.
Total candy bars : [tex]5+10+13+12+17=57[/tex]
Probability of getting a Milky Way bar=[tex]p=\dfrac{\text{No. of Milky bars}}{\text{Total candy bars}}[/tex]
[tex]\Rightarrrow\ p=\dfrac{13}{57}\approx0.23[/tex]
Using Binomial distribution , the probability of getting success in x trials is given by:-
[tex]P(x)=^nC_xp^x(1-p)^{n-x}[/tex], where p uis probability of success in each trial and n is sample size.
If you randomly select n= 5 candy bars, then the probability you select exactly 2 Milky Way bars Will be :_
[tex]P(2)=^5C_2(0.23)^2(1-0.23)^{3}\\\\=\dfrac{5!}{2!(5-2)!}(0.23)^2(0.77)^3\\\\=0.241505957\approx0.2415[/tex]
Hence, the probability you select exactly 2 Milky Way bars = 0.2415
