Question

Jean and Fred are making apple crisp. The recipe calls for 8 apples to be peeled and cut into pieces. However, as Fred and Jean work, they eat pieces of apple. Fred eats 2/9 of each apple that he peels, and Jean eats 1/9 of each apple she peels. Assuming they each peel and cut four apples, how many apples will they have left over for the recipe after they peel eight apples?

Answer 1

Answer:

$\frac{20}{3} = 6\frac{2}{3}$ i.e. six and two-third apples will be left.

Step-by-step explanation:

Fred eats $\frac{2}{9}$ of each apple that he peels and Jean eats $\frac{1}{9}$ of each apple that he peels.

So, if Fred peels 4 apples then he eats $\frac{4 \times 2}{9} = \frac{8}{9}$ of one apple.

And, if Jean peels 4 apples then he eats $\frac{4 \times 1}{9} = \frac{4}{9}$ of one apple.

Hence, total they peel (4 + 4) = 8 apples but they eat total $(\frac{8}{9} + \frac{4}{9}) = \frac{12}{9} = \frac{4}{3}$ apples

Therefore, they will have left $8 - \frac{4}{3} = \frac{24 - 4}{3} = \frac{20}{3} = 6\frac{2}{3}$ {Since 20 = 6 × 3 + 2 } apples for the recipe after they peel eight apples. (Answer)