Answer:
The 0 and 1 outcomes would be considered unusual.
Step-by-step explanation:
We can define as usual outcomes, the ones that fall between [tex]\bar{x}\pm 3s[/tex].
According to a binomial distribution, s value is
[tex]s=\sqrt{n*p*(1-p)}\\s=\sqrt{8*0.65*(1-0.65)}\\s=\sqrt{1.82}=1.35[/tex]
The expected value out of a 8 people sample is
[tex]\bar{x}=p*n=0.65*8=5.2\\[/tex]
Then, our interval of usual values lies between
[tex]\bar{x}- 3s\leq x \leq \bar{x} +3s\\\\5.20-3*1.35\leq x \leq 5.20+3*1.35\\1.15\leq x \leq 9.25[/tex]
We can conclude that 0 and 1 (the results that lie outside of the interval) are unusual.