Answer:
[tex]y=x+1[/tex]
Step-by-step explanation:
Your generic line will be [tex] y= mx+q [/tex], so you'll need two condition.
Since it has to be perpendicular to [tex]y=(-1)x+2[/tex], the product of the slopes needs to be -1, or [tex]m(-1)=-1[/tex], hence your "generic" becomes [tex]y=x+q[/tex]. Since it has to pass through [/tex](-5;-4), let's put the coordinates in there: [tex](-4)=1(-5)+q
q-5=-4
q=1[/tex]
your line becomes [tex]y=x+1[/tex]
