[tex]\frac{x\cdot \:4-5x\cdot \:3-8x\cdot \:2+13x-12}{x-6} \ \textgreater \ x\cdot \:4-5x\cdot \:3-8x\cdot \:2+13x-12[/tex]
[tex]\mathrm{Add\:similar\:elements:}\:4x+13x=17x \ \textgreater \ 17x-3\cdot \:5x-2\cdot \:8x-12[/tex]
[tex]\mathrm{Refine\; it} \ \textgreater \ 17x-15x-16x-12 [/tex]
[tex]\mathrm{Add\:similar\:elements:}\:17x-15x-16x= \ \textgreater \ -14x-12 \ \textgreater \ \frac{-14x-12}{x-6}[/tex]
[tex]Therefore\;our\;final\;answer\;is\; \frac{-14x-12}{x-6}[/tex]
Hope this helps!
