Question

9. If a rocket flies north 390 meters in 6 seconds, what is its velocity?

Answer 1

Answer:

65 m/s north

Explanation:

The velocity of an object is given by:

$v=\frac{d}{t}$

where

d is the displacement of the object

t is the time interval needed for the displacement

For the rocket in this problem,

d = 390 m north

t = 6 s

So the velocity is

$v=\frac{390}{6}=65 m/s$ north

It is important to keep in mind that velocity is a vector, so it both has a magnitude (65 m/s) and a direction (which is equivalent to that of the displacement, so in this case north).