Question

Calcium ion (Ca2+) is necessary for the clotting of blood and many other physiological processes. A particular alien race has similar physiological processes except their concentration of Ca2+ in blood is much higher than in humans. To measure the Ca2+ concentration in 1.00 ml of alien blood, sodium oxalate (Na2C2O4) solution is added, which precipitates the Ca2+ as CaC2O4. This solid is dissolved in dilute sulfuric acid to release C2O42LaTeX: -−, and 18.03 ml of 0.644 M potassium permanganate is required to reach the end point. The balanced equation is 2KMnO4(aq) + 5CaC2O4(s) + 8 H2SO4(aq) LaTeX: \longrightarrow⟶ 2MnSO4 (aq) + K2SO4(aq) + 5CaSO4(s) +10 CO2(g) +8H2O(l) Calculate the amount (in mol) of Ca2+ in 1.00 ml of alien blood. Enter to 4 decimal places

Answer 1

Answer:

There are 0.0290 moles of Ca⁺² in 1.00 mL of alien blood.

Explanation:

The reactions that take place is:

Ca⁺²(aq) + Na₂C₂O₄(aq) → CaC₂O₄(s) + 2Na⁺

2KMnO₄(aq) + 5CaC₂O₄(s) + 8 H₂SO₄(aq) → 2MnSO₄ (aq) + K₂SO₄(aq) + 5CaSO₄(s) +10 CO₂(g) +8H₂O(l)

It's important to keep this last reaction in mind in order to know the stoichiometric ratio between KMnO₄ and CaC₂O₄.

Using the concentration of KMnO₄ and its volume, we can calculate how many moles there are, then we can convert them into moles of CaC₂O₄ and finally into moles of Ca⁺²:

• First we convert 18.03 mL into L: 0.01803 L, respectively.

• Then we convert moles, keeping the moles that we want to convert in the denominator, and the moles that we want to convert to in the numerator. While keeping in mind the stoichiometric ratio:

$0.644 M * 0.01803 L *\frac{5moles CaC2O4}{2molesKMnO4}*\frac{1molCa^{+2} }{1molCaC2O4}=0.0290 molesCa^{+2}$

There are 0.0290 moles of Ca⁺² in 1.00 mL of alien blood.

Answer 2

We want to measure the Ca²⁺ concentration in 1.00 ml of alien blood, so sodium oxalate solution is added, which precipitates the Ca²⁺ as CaC₂O₄, which then reacts with H₂SO₄ and 18.03 mL of 0.644 M KMnO₄. As a result, we can conclude that there are 0.0290 moles of Ca²⁺ in the alien's blood.

Let's consider the following 2 reactions:

Ca²⁺ + Na₂C₂O₄ ⟶ CaC₂O₄ + 2 Na⁺

2 KMnO₄(aq) + 5 CaC₂O₄(s) + 8 H₂SO₄(aq) ⟶ 2 MnSO₄ (aq) + K₂SO₄(aq) + 5 CaSO₄(s) + 10 CO₂(g) + 8 H₂O(l)

18.03 mL of 0.644 M KMnO₄ reacts in the second reaction. The reacting moles of KMnO₄ are:

$0.01803 L \times \frac{0.644mol}{L} = 0.0116mol$

In the second reaction, the molar ratio of KMnO₄ to CaC₂O₄ is 2:5. The reacting moles of CaC₂O₄ are:

$0.0116molKMnO_4 \times \frac{5molCaC_2O_4}{2molKMnO_4} = 0.0290molCaC_2O_4$

The molar ratio of CaC₂O₄ to Ca²⁺ is 1:1. The moles of Ca²⁺ in 1.00 ml of alien blood is:

$0.0290molCaC_2O_4 \times \frac{1molCa^{2+} }{1molCaC_2O_4} = 0.0290molCa^{2+}$

We want to measure the Ca²⁺ concentration in 1.00 ml of alien blood, so sodium oxalate solution is added, which precipitates the Ca²⁺ as CaC₂O₄, which then reacts with H₂SO₄ and 18.03 mL of 0.644 M KMnO₄. As a result, we can conclude that there are 0.0290 moles of Ca²⁺ in the alien's blood.

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