Question

Against the wind a small plane flew 715 miles in 2 hours and 10 minutes. The return trip took only 1 hour and 50 minutes. What was the speed of the​ wind? What was the speed of the plane in still​ air?

Answer 1

Answer:

  360 mi/h

Step-by-step explanation:

The speed for the outbound trip was ...

  speed = distance/time = (715 mi)/(2 1/6 h) = 330 mi/h

The inbound speed was ...

  (715 mi)/(1 5/6 h) = 390 mi/h

The airspeed of the plane is the average of these two ground speeds, so is ...

  (330 +390)/2 = 360 . . . . mi/h