Answer:
The final temperature of water = 22.1224 °C
Explanation:
Step 1 : defien the formula for heat transfer
q = m*c*ΔT
with q = heat transfer
with m = mass of the substance
with c = specific heat ( of water in this case)
with ΔT = difference between final temperature and initial temperature
In this case :
q=366kJ = 366 *10^3 J
mass of water = 48kg = 48000g
c= specific heat of wwater = 4.184 J / g °C
initial temperature = 20.3 °C
final temperature = TO BE DETERMINED
Step 2: Calculate temperature
366000 J = 48000g * 4.184J/g °C * (T2 - 20.3)
366000 / (480000 * 4.184) = 1.8224 = (T2 - 20.3)
T2 = 20.3 + 1.82 =22.1224 ° C
The final temperature of water = 22.1224 °C
