Answer:
Explanation:
We shall apply Stefan- Boltzmann Law of black body radiation here which is applied to radiation made by black body in a particular surrounding.
E = σ A ( T⁴₀ - T⁴ )
Energy E is radiated by surface area A of a black body per second having absolute temperature of T₀ and having surrounding temperature of T.
Given T₀ = 30 degree = 303 K.
T = 288 K
A = 275 m²
σ = constant =5.67 x 10⁻⁸ Wm⁻²s⁻¹
Putting these values in the relation written above
E = 5.67 X 10⁻⁸ X 275 ( 303⁴ - 288⁴ )
= 5.67 X 10⁻⁸ X 275 (84.28 - 68.79) 10⁵
24.15 J A⁻¹ S⁻¹
