Answer:
a) 0.975 m
b) 13.25 m
Explanation:
given data:
pressure gage reading 130 kPa
a) mercury with density 13,600 kg/m^3
let distance between two fluid level is h,
then
we know that [tex]p = \rho g h[/tex]
13600*9.8*h=130*10^3
so h = 0.975 m
b.) water with density 1000 kg/m^3
let distance between two fluid level is h,
then
we know that [tex]p = \rho g h[/tex]
1000*9.8*h= 130*10^3
so h= 13.25 m