Question

Suppose you place 125 g of aluminum in a calorimeter with 1,000 g of water. The water changes temperature by 2 °C and the aluminum changes temperature by –74.95 °C.

Water has a known specific heat capacity of 4.184 J/g °C. Use the specific heat equation to find out how much heat energy the water gained (q).

Answer 1

Answer: The amount of heat gained by the water is 8368 J

Explanation:

To calculate the amount of heat absorbed, we use the equation:

$q=m\times C\times \Delta T$

where,

q = amount of heat absorbed = ?

m = mass of water = 1000 g

C = specific heat capacity of water = 4.184 J/g°C

$\Delta T$ = change in temperature = 2°C

Putting all the values in above equation, we get:

$q=1000g\times 4.184J/g^oC\times 2^oC\\\\q=8368J$

Hence, the amount of heat gained by the water is 8368 J

Answer 2

The first law of thermodynamics state that can never be created nor be destroyed it can only be transferred from one place to another. For example heat energy.

The heat energy gained by the water molecule is 8368J.

The solution is as follows:-

According to the question, the formula we gonna uses it.

$q =m*C*T$

In this equation,

• Q stands for heat absorbed,
• m stands for mass,
• T stands for time,
• C is constant.

All the data is given in the question, after putting it in the equation.

$q = 1000* 4.184*2\\\\=8368J$

Hence, the heat gained is 8368J.

For more information, refer to the link:-

https://brainly.com/question/25384702