Answer:
So the statement:
"The product of two irrational numbers is rational." is false.
Step-by-step explanation:
The product of two irrationals can be irrational or rational.
Example:
[tex]\sqrt{2} \cdot \sqrt{2}=2[/tex]
[tex]\sqrt{2}[/tex] is irrational but when you multiply it to itself the output is rational.
Example:
[tex]\sqrt{2} \cdot \sqrt{3}=\sqrt{6}[/tex]
[tex]\sqrt{2} \text{ and } \sqrt{3}[/tex] are irrational and when you multiply them you get an irrational answer of [tex]\sqrt{6}[/tex].
So the statement:
"The product of two irrational numbers is rational." is false.