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A carpenter purchased 50 ft of redwood and 90 ft of pine for a total cost of $274. A second purchase at the same prices include 80 ft of redwood and 50 ft of pine for a total cost of 335. Find the cost per foot of redwood and of pine

Respuesta :

Answer:

Redwood: $3.50 per foot

Pine: $1.10 per foot

Step-by-step explanation:

The manner that should be approach is by using the substitution method.

Therefore using the information from the question:

50 ft of redwood and 90 ft of pine give a total cost of $274

So we use this information and make a equation using x and y, in this case redwood would be x and pine would be y.

[tex]50x + 90y=274[/tex]

We do this for the second purchase also...

[tex]80x+50y=335[/tex]

Now, we have two equations that are perfect for the usage of the substitution method.

[tex]50x + 90y=274[/tex]

[tex]80x+50y=335[/tex]

Using one equation, in this case the top one, we must solve for either x or y (in this case we solved for y)

[tex]90y=274-50x[/tex]

[tex]\frac{90y}{90} =\frac{274}{90} -\frac{50x}{90}[/tex]

[tex]y=\frac{274}{90} -\frac{50x}{90}[/tex]

Using this equation from above we insert this into the other equation that deals with the second purchase and solve for x now.

[tex]80x+50(\frac{274}{90} -\frac{50x}{90})=335[/tex]

[tex]80x+152.2-27.8x=335[/tex]

[tex]80x-27.8x=182.8[/tex]

[tex]\frac{52.2x}{52.2} =\frac{182.8}{52.2}[/tex]

[tex]x=3.50[/tex]

This is the cost of redwood so now we use this answer and plug it in either equation in order to get the cost of pine (y).

[tex]50(3.5)+90y=274[/tex]

[tex]175+90y=274[/tex]

[tex]\frac{90y}{90}=\frac{99}{90}[/tex]

[tex]y=1.1[/tex]

So therefore you get the two costs by using the substitution method!

~~~~Best!!!

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