Question

A city wants to show that the mean number of public transportation users per day is more than 5,575. Identify the null hypothesis, H0, and the alternative hypothesis, Ha, in terms of the parameter μ.

Answer 1

Answer:

$H_0:\mu\leq 5575$

$H_a:\mu > 5575$

Step-by-step explanation:

Given : A city wants to show that the mean number of public transportation users per day is more than 5,575.

To Find : Identify the null hypothesis, $H_0$, and the alternative hypothesis, $H_a$ , in terms of the parameter μ.

Solution:

Claim :  A city wants to show that the mean number of public transportation users per day is more than 5,575.

So, Null hypothesis :$H_0:\mu\leq 5575$

Alternate hypothesis :$H_0:\mu > 5575$

Answer 2

Answer:

H0: μ≤5,575; Ha: μ>5,575

Step-by-step explanation:

Let the parameter μ be used to represent the mean.

Remember that the null hypothesis is the statement already believed to be true, and the alternative hypothesis is the statement trying to be shown. In this case, the city is trying to show that μ>5,575, so this is the alternative hypothesis. The null hypothesis is the opposite of this: μ≤5,575.

Also, remember that the null hypothesis is always stated with some form of equality: equal (=), greater than or equal to (≥), or less than or equal to (≤). So we can double check that this matches our answer above.