Explanation:
The wave equation which is propagating down a string of unknown material is given by :
[tex]y(x,t)=15\ sin(6t-7x)[/tex]................(1)
The general equation of wave is given by :
[tex]y=A\ sin(\omega t-kx)[/tex]..............(2)
Comparing equation (1) and (2) we get:
(a) [tex]\omega=6[/tex]
[tex]2\pi f=6[/tex]
f = 0.954 Hz
(b) Radian frequency, [tex]\omega=6\ rad/s[/tex]
(c) k = 7
[tex]\dfrac{2\pi}{\lambda}=7[/tex]
[tex]\lambda=0.89\ m[/tex]
(d) Wave number, [tex]k=5\ m^{-1}[/tex]
(e) Speed of sound, [tex]v=f\times \lambda[/tex]
[tex]v=0.954\times 0.89[/tex]
v = 0.849 m/s
Hence, this is the required solution.