Respuesta :
Figure 1 (tallest): height (h) = 7
Figure 2: h = 7 - 1 = 6
Figure 3: h = 6 - 1 = 5
Figure 4: h = 5 - 1 = 4
Figure 5: h = 4 - 1 = 3
Figure 6: h = 3 - 1 = 2
Figure 7 (shortest): h = 2 - 1 = 1
Let's use a rectangular prism to demonstrate how height affects surface area.
(I am making the assumption that the length and width are the same for all seven figures.)
S.A.(tallest)= 2(L x w) + 2(w x h) + 2(L x h)
588 = 2(L x w) + 2(w x 7) + 2(L x 7)
588 = 2Lw + 14w - 14L
Solve for one of the variables (I am choosing to solve for w):
588 - 14L = 2Lw + 14w
588 - 14L = 2w(2L + 7)
[tex] \frac{588 - 14L}{2(2L + 7)} = w[/tex]
[tex] \frac{294 - 7L}{2L + 7} = w[/tex]
Now, plug w into the equation for the surface area of the shortest figure:
reminder that the height of the shortest figure is 1 in (h = 1)
S.A. (shortest) = 2(L x w) + 2(w x h) + 2(L x h)
= 2(L x w) + 2(w) + 2(L)
= 2L · [tex] \frac{294 - 7L}{2L + 7}[/tex] + 2 · [tex] \frac{294 - 7L}{2L + 7}[/tex] + 2L
= [tex] \frac{588L - 14L^{2} + 588L -14L + 4L^{2} + 14L}{2L + 7} [/tex]
= [tex] \frac{-10L^{2} + 1176}{2L + 7} [/tex]
I cannot go any further without knowing the length.
Hope this is what you are looking for!
Figure 2: h = 7 - 1 = 6
Figure 3: h = 6 - 1 = 5
Figure 4: h = 5 - 1 = 4
Figure 5: h = 4 - 1 = 3
Figure 6: h = 3 - 1 = 2
Figure 7 (shortest): h = 2 - 1 = 1
Let's use a rectangular prism to demonstrate how height affects surface area.
(I am making the assumption that the length and width are the same for all seven figures.)
S.A.(tallest)= 2(L x w) + 2(w x h) + 2(L x h)
588 = 2(L x w) + 2(w x 7) + 2(L x 7)
588 = 2Lw + 14w - 14L
Solve for one of the variables (I am choosing to solve for w):
588 - 14L = 2Lw + 14w
588 - 14L = 2w(2L + 7)
[tex] \frac{588 - 14L}{2(2L + 7)} = w[/tex]
[tex] \frac{294 - 7L}{2L + 7} = w[/tex]
Now, plug w into the equation for the surface area of the shortest figure:
reminder that the height of the shortest figure is 1 in (h = 1)
S.A. (shortest) = 2(L x w) + 2(w x h) + 2(L x h)
= 2(L x w) + 2(w) + 2(L)
= 2L · [tex] \frac{294 - 7L}{2L + 7}[/tex] + 2 · [tex] \frac{294 - 7L}{2L + 7}[/tex] + 2L
= [tex] \frac{588L - 14L^{2} + 588L -14L + 4L^{2} + 14L}{2L + 7} [/tex]
= [tex] \frac{-10L^{2} + 1176}{2L + 7} [/tex]
I cannot go any further without knowing the length.
Hope this is what you are looking for!