Answer:
Step-by-step explanation:
Given that four dice are rolled.
Probability for getting 4 in any dice = [tex]\frac{1}{6}[/tex] and
Probability for getting 2 in any dice = [tex]\frac{1}{6}[/tex]
Since each die is independent of the other the probability would be
= [tex]4C1(\frac{1}{6})^3( \frac{1}{6})\\=0.003086[/tex]
Explanation:
2 can occur either I or II or III or Iv hence we multiply by 4C1 and multiply 1/6, 4 times.
