Respuesta :
Question:
What is the end behavior of this radical function?
[tex]f\left(x\right)=3\sqrt[3]{x-4}[/tex]
1. As x approaches positive infinity, f(x) approaches positive infinity.
2. As x approaches negative infinity, f(x) approaches positive infinity.
3. As x approaches positive infinity, f(x) approaches negative infinity.
4. As x approaches negative infinity, f(x) approaches 0.
Answer:
1. As x approaches positive infinity, f(x) approaches positive infinity.
Explanation:
In photo below


Using limits, it is found that the statement which describes the end behavior of the function f(x) is:
B. As x approaches negative infinity, f(x) approaches positive infinity.
How we find the end behavior of a function f(x)?
It is given by the limit of f(x) as x approaches both positive infinity and negative infinity.
In this problem, the function is:
[tex]f(x) = \frac{1}{7}|x - 4| + 3[/tex]
Hence, the limits are:
[tex]\lim_{x \rightarrow -\infty} f(x) = \lim_{x \rightarrow -\infty} = \frac{1}{7}|x - 4| + 3 = \frac{1}{7}|-\infty - 4| + 3 = \infty[/tex]
[tex]\lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} = \frac{1}{7}|x - 4| + 3 = \frac{1}{7}|\infty - 4| + 3 = \infty[/tex]
Approaches positive infinity in both cases, hence option B is correct.
You can learn more about limits and end behavior at https://brainly.com/question/22026723