Question

a bicycle and its rider together have a mass of 80 kg. if the bicycle's speed is 6m/s, how much force is needed to bring it to a stop in 4 seconds.

Answer 1

Answer:

$\huge\boxed{\sf F = 120 \ N}$

Explanation:

Given data:

Mass = m = 80 kg

Initial velocity = $V_i$ = 0 m/s

Final velocity = $V_f$ = 6 m/s

Time = t = 4 s

Required:

Force = F = ?

Formula:

$\displaystyle F=\frac{m(v_f-v_i)}{t}$

Solution:

Put the given data in the above formula.

Finding force.

$\displaystyle F=\frac{80(6-0)}{4} \\\\F = \frac{80(6)}{4} \\\\F = 20(6)\\\\F = 120 \ N\\\\\rule[225]{225}{2}$