Answer:
[tex]F=3300 *10^{-3} N[/tex]
Explanation:
The electric field is defined as the electric force (F) per unit of charge (q) . The formula to calculate electric field (E) is:
[tex]E=\frac{F}{q}[/tex] Formula (1)
Where:
E: Electric field in [tex]\frac{N}{C}[/tex]
F: Force in Newtons(N)
q = Electric charge in Coulombs(C)
We know the following data:
[tex]E=660 \frac{N}{C}[/tex]
q =5 mC , [tex]1 mC=1*10^{-3} C[/tex] ,then, [tex]q=5 *10^{-3} C[/tex]
Development of the problem:
In formula (1 ) We replace the known data :
[tex]E=\frac{F}{q}[/tex]
[tex]660 \frac{N}{C} =\frac{F}{5 *10^{-3}C}[/tex]
[tex]F =660 \frac{N}{C}* 5 *10^{-3} C[/tex]
[tex]F=3300 *10^{-3} N[/tex]