Answer:
The energy stored in the conductor is 5×10^-8 J.
Explanation:
let v be the potential of the conductor.
let Q be the charge on the conductor.
let k = 9×10^9 be the coulomb constant.
let r be the radius of the conductor.
then, the potential of the conductor is given by:
V = k×Q/r
Q = V×r/k
= [(100)×(9×10^-2)]/(9×10^9)
= 1×10^-9 C
then, the energy stored in the conductor is given by:
E = 1/2×Q×V
= 1/2×(1×10^-9)×(100)
= 5×10^-8 J
Therefore, the energy stored in the conductor is 5×10^-8 J.