Question

An amusement park ride consists of a rotating circular platform 7.33 m in diameter from which 10 kg seats are suspended at the end of 2.45 m massless chains. When the system rotates, the chains make an angle of 43.7 ◦ with the vertical. The acceleration of gravity is 9.8 m/s 2 . What is the speed of each seat?

Answer 1

Answer:

speed is 9.94 m/s

Explanation:

given data

diameter = 7.33 m

mass = 10 kg

distance = 2.45 m

angle = 43.7°

acceleration of gravity = 9.8 m/s²

to find out

speed of each seat

solution

for speed we will apply here formula that is express as

speed = √(Rg/tanθ )    ......................1

put here all value in equation 1 we get

here R = diameter /2 + mass sin43.7

R = 7.33/2 + 10(0.690)

R= 10.565 m

speed =  √(10.565(9.8)/tan(90-43.7) )

speed = 9.94 m/s