Question

Cube A has an edge length of 2 and cube B has an edge length of 6. How many times greater is the volume of cube B than cube A?

Answer 1

volume of cube A = 2 × 2 × 2 = 8

volume of cube B = 6 × 6 × 6 = 216

216 ÷ 8 = 27

Therefore it is 27 times greater

Answer 2

The volume of a shape is the amount of space, the shape can contain. The volume of B is 27 times greater than the volume of A

Given that:

$L_A = 2$ --- length of cube A

$L_B = 6$ --- length of cube B

First, we calculate the volume of both cubes using:

$Volume =Length^3$

So, we have:

$V_A = 2^3$

$V_A = 8$

and

$V_B = 6^3$

$V_B = 216$

The number of times (n) volume B is greater than A is:

$n = \frac{V_B}{V_A}$

$n = \frac{216}{8}$

$n = 27$

Hence, the volume of B is 27 times greater than the volume of A

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