Question

what is the horizontal distance between these two points (3,4) and (8,4)

Answer 1

Answer:

5 units

Step-by-step explanation:

Here we are given with two coordinates and asked to determine the distance between them.

Here we are going to use the distance formula, which is given as under

 

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

 

Where

$(x_1,y_1) = (3,4)$

$(x_2,y_2) = (8,4)$

 

Replacing these values in the distance formula

$D =\sqrt{(3-8)^2+(4-4)^2}$

$D =\sqrt{(-5)^2+(0)^2}$

$D =\sqrt{25}$

$D= 5$

 

Hence the Distance is 5 units