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The Perimeter of a Triangular Field is 420m and its sides are in the ratio 6:7:8. Find its Area.​

Respuesta :

Answer:

A ≈ 8133.27 m²

Step-by-step explanation:

Sum the parts of the ratio 6 + 7 + 8 = 21 parts

Divide the perimeter by 21 to find the value of one part

420 ÷ 21 = 20 ← value of 1 part of the ratio, hence sides of triangle are

6 × 20 = 120

7 × 20 = 140

8 × 20 = 160

To calculate the area (A) we can use Hero's formula

A = [tex]\sqrt{s(s-a)(s-b)(s-c)}[/tex]

Where s is the semi perimeter and a, b, c the sides of the triangle

let a = 120, b = 140 , c = 160 and s = 420 ÷ 2 = 210

A = [tex]\sqrt{210(210-120)(210-140)(210-160)}[/tex]

   = [tex]\sqrt{210(90)(70(50)}[/tex]

   = [tex]\sqrt{66150000}[/tex] ≈ 8133.27 m²

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