Question

One number is 4 less than 3 times a second number. If 3 more than two times the first number is decreased by two times the second the result is 11. What are both numbers?

Answer 1

$x-\ first\ number\\ y-\ second\ number\\\\\ x+4=3y\ \ \ \ x=3y-4\\ 2x+3-2y=11\\\\ 2(3y-4)+3-2y=11\\\\ 6y-8+3-2y=11\\\\ 4y-5=11\ \ \ | add \ 5\\\\ 4y=16\ \ \ | divide\ by\ 4\\\\ y=4\\ x=3*4-4=12-4=8\\\\ Number\ are:\ 4\ and\ 8.$